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Determine the standard form of the equation of the line that passes through (-2, 0) and (-8, 5).

5x + 6y = 10
5x - y = - 10
6x + 5y = - 10
d. 5x + y = -10
C.
b.
Please select the best answer from the choices provided
A
B
С
D

User Yu Zhou
by
8.3k points

1 Answer

6 votes

Answer:

5x + 6y = -10

Explanation:

(-2, 0) and (-8, 5)

m = (y₂ - y₁) / (x₂ - x₁)

m = (5 - 0) / (-8 -(-2)

m = 5 / (-8+2)

m = -5/6

y = mx + b

(-8, 5)

5 = -5/6(-8) + b

5 = 40/6 + b

b = 5 - 40/6

b = -5/3

y = mx + b

y = -5/6x - 5/3 *6

6y = -5x -5(2)

6y = -5x - 10

5x + 6y = -10

User Mushtaq Jameel
by
7.9k points

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