Question

Katie has a collection of nickels, dimes and quarters with a total value of $3.95. There are 4 more dimes than nickels and 3 more quarters than nickels, how many of each coin does she have?

Answer 1

She has 7 nickels, 11 dimes and 10 quarters

Explanation:

Total value =$3.95

Let

Nickel = x

Dimes = x + 4

Quarters = x + 3

Every

Nickel = 5 cents

Dimes = 10 cents

Quarters = 25 cents

Total cents = $3.95 × 100

= $395

5n + 10d + 25q = 395

5(x) + 10(x+4) + 25(x+3) = 395

5x + 10x + 40 + 25x + 75 = 395

40x + 115 = 395

40x = 395 - 115

40x = 280

Divide both sides by 40

x= 280/40

= 7

x= 7

Nickel = x = 7

Dimes = x + 4

=7+4

=11

Quarters = x + 3

=7+3

=10