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The sum of 6 consecutive integers is 339.

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Answer:

54, 55, 56, 57, 58, and 59 are the numbers

Explanation:

Let's pretend that the first number is
n.

We know that these numbers are consecutive, meaning each number is one more than the other.

This means that


n + (n+1)+ (n+2)+ (n+3)+ (n+4)+ (n+5) = 339, since each number is consecutive.

We can combine like terms to get
6n + 15 = 339.

Now let's solve for n.


6n + 15 - 15 = 339-15\\\\6n = 324\\\\n = 54

So
n=54. This means the other 5 digits will be one more than the next.

So 54, 55, 56, 57, 58, and 59.

Hope this helped!

User Okrutny
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