Answer:
b = 8tan30°
Explanation:
Find the diagram of the triangle in the attachment. Using SOH CAH TOA to find the side AC which is b. Side AC will be the opposite of the triangle since it is facing the acute angle 30° and side BC will be adjacent.
Using TOA;
Tan<CBA = CA/BC
Given <CBA = 30°, BC = 8feet
CA = BCtan<CBA
CA = 8tan30° = b
Hence the equation that can be used to solve for b is 8tan30°