Question

16. Write the equation of line that contains
the points (1, 2) and (3, 0).

Answer 1

[see below]

Explanation:

Finding Slope:

m =
`(rise)/(run)=(0-2)/(3-1)=(-2)/(2)=-1`

Using the slope and a point to make a point slope equation:

`y-y_1=m(x-x_1)`

m = -1 (x,y) = (1,2)

Plug values:

`y-2=-1(x-1)`

Convert the equation into slope-intercept:

`y-2=-1(x-1)\\\\y-2=-1x+1\\\\y-2+2=-1x+1+2\\\\y=-1x+3\\\\\boxed{y=-x+3}`

Hope this helps.

Answer 2

y=-1x+3

I honestly have no idea how I would explain this. Apologies.