Question

Find an equation of the line passing through the points (−8,2) with the slope m= 4/3

Answer 1

`y=(4)/(3)x+(38)/(3)`

Explanation:

So we want to find an equation of a line passing through (-8,2) with a slope of 4/3.

To do so, we can use the point-slope form. This is:

`y-y_1=m(x-x_1)`

So, substitute (-8,2) for x₁ and y₁, and let m be 4/3:

`y-2=(4)/(3)(x+8)`

Distribute the right:

`y-2=(4)/(3)x+(32)/(3)`

Add 2 to both sides. Note that 2 can be written as 6/3. Thus:

`y=(4)/(3)x+(32)/(3)+(6)/(3)`

Simplify:

`y=(4)/(3)x+(38)/(3)`

And this is our equation :)