153k views
4 votes
The point-slope form of the equation that passes through (-4, -3) and (12, 1) is y - 1 = 1/4(x-12). what is the standard form of the equation for this line?

A) x-4y=8
B) x-4y=2
C) 4x-y=8
D) 4x-y=2

User Leesha
by
8.7k points

1 Answer

4 votes

Answer:

A

Explanation:

So we know that the point-slope form of the line that passes through the points (-4,-3) and (12,1) is:


y-1=(1)/(4)(x-12)

And we want to convert this to standard form.

The standard form of a linear equation is:


Ax+By=C

Where A, B, and C are integers, and, traditionally, A is positive.

So, first, multiply everything by 4 to remove the negative:


4(y-1)=4((1)/(4)(x-12))

Distribute the left. The right cancels:


4y-4=x-12

Add 4 to both sides. The left cancels:


4y=x-8

Subtract x from both sides:


-x+4y=-8

As I mentioned previously, the coefficient of A tends to be positive. So, divide everything by -1:


(-x+4y)/-1=(-8)/-1

Simplify:


x-4y=8

So, our answer is A

And we're done!

User Mozharovsky
by
7.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories