Question

Find an equation of the line passing through the point (−6,−5) that is parallel to the line y=4/3x−5

Answer 1

The answer is

`y = (4)/(3) x + 3`

Explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

y = 4/3x - 5

Comparing with the general equation above

Slope/ m = 4/3

Since the lines are parallel their slope are also the same

So we have

Slope of parallel line = 4/3

Equation of the line using point (−6,−5) and slope 4/3 is

`y + 5 = (4)/(3) (x + 6) \\ y + 5 = (4)/(3) x + 8 \\ y = (4)/(3) x + 8 - 5`

We have the final answer as

`y = (4)/(3) x + 3`

Hope this helps you.