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The length of a rectangle is 5 mm less than 4 times the width. If the perimeter is 75 mm, what is the length of the rectangle?

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Answer:


\boxed{ \bold{ \huge{ \boxed{ \sf{29 \: mm}}}}}

Explanation:

Let the width of a rectangle be 'w'

Length of a rectangle be 4w - 5

Perimeter of a rectangle = 75 mm

First, finding the width of the rectangle ( w )


\boxed{ \sf{perimeter \: of \: a \: rectangle = 2(length + width)}}


\dashrightarrow{ \sf{75 = 2(4w - 5 + w)}}


\dashrightarrow{ \sf{75 = 2(5w - 5)}}


\dashrightarrow{ \sf{75 = 10w - 10}}


\dashrightarrow{ \sf{10w - 10 = 75}}


\dashrightarrow{ \sf{10w = 75 + 10}}


\dashrightarrow{ \sf{10w = 85}}


\dashrightarrow{ \sf{ (10w)/(10) = (85)/(10) }}


\dashrightarrow{ \sf{w = 8 .5 \: mm}}

Replacing / substituting the value of width of a rectangle in order to find the length of a rectangle


\sf{length \: of \: a \: rectangle = 4w - 5}


\dashrightarrow{ \sf{4 * 8.5 - 5}}


\dashrightarrow{ \sf{34 - 5}}


\dashrightarrow{ \sf{29 \: mm}}

Length of a rectangle = 29 mm

Hope I helped!

Best regards! :D

User Rocknroll
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