Answer:
It has exactly 3 congruent sides.
Explanation:
Since ∠FGJ = ∠JGH = 30° and GJ is a perpendicular bisector of FH, ∠GJF = 90°. So in ΔFGJ, ∠FGJ + ∠GJF + ∠GFJ = 180°.
So, 30° + 90° + ∠GFJ = 180°
120° + ∠GFJ = 180°
∠GFJ = 180° - 120°
∠GFJ = 60°
Also, since GJ is the perpendicular bisector of FH, ∠GJH = 90°. So in ΔJGH, ∠JGH + ∠GJH + ∠JHG = 180°.
So, 30° + 90° + ∠JHG = 180°
120° + ∠JHG = 180°
∠JHG = 180° - 120°
∠JHG = 60°
Since ∠FGH = ∠FGJ + ∠JGH = 30° + 30° = 60°
Since ∠FGH = ∠GFJ = ∠JHG = 60°
So, ΔFGJ is an equilateral triangle. Since all its angles are equal, so also, all its sides are equal. So, ΔFGJ is congruent by SSS and AAA so its 3 sides are congruent.
So exactly 3 sides are congruent in ΔFGJ.