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Find the solutions of the quadratic equation 5x^2 +3x+1=0

1 Answer

4 votes

Answer:

The answer is


x = - (3)/(10) + ( √(11) )/(10) \: i \\ \\ \: OR \\ \\ x = - ( 3)/(10) - ( √(11) )/(10) \: i

Explanation:

5x² + 3x + 1 = 0

Using the quadratic formula


x = \frac{ - b\pm \sqrt{ {b}^(2) - 4ac } }{2a}

From the question

a = 5 , b = 3 , c = 1

Substitute the values into the above formula and solve

That's


x = \frac{ - 3\pm \sqrt{ {3}^(2) - 4(5)(1) } }{2(5)} \\ x = ( - 3\pm √(9 - 20) )/(10) \\ x = ( - 3\pm √( - 11) )/(10) \\ x = ( - 3\pm √(11 ) \: i)/(10) \\ x = ( - 3 + √(11) \: i)/(10) \: \: or \: \: \: x = ( - 3 - √(11) \: i)/(10)

Separate the real and imaginary parts

We have the final answer as


x = - (3)/(10) + ( √(11) )/(10) \: i \\ \\ x = - ( 3)/(10) - ( √(11) )/(10) \: i

The equation has complex roots

Hope this helps you

User ChaseMoskal
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