Question

3(y+3)+7(2y-8)-(y-1)=0​

Answer 1

Explanation:

3(y+3)+7(2y-8)-(y-1)=0​

3y + 9 + 14y - 56 - y + 1 = 0

16y - 46 = 0

16y - 46 + 46 = 0 + 46

16y = 46

16y/16 = 46/16

y = 23/8

Answer 2

We have this equation:

`3(y+3)+7(2y-8)-(y-1)=0​`

First, we do the parenthesis:

`3y+9+14y-56-(y-1)=0\\`

When there is a minus (-) in front of a parenthesis, all signs change inside it:

`3y+9+14y-56-y+1)=0\\`

Now we operate:

`16y-46=0`

We add 46 on both sides:

`16y - 46 + 46 = 0 +46`

`16y = 46`

And divide 16 on both sides:

`(16y)/(16)=(46)/(16)`

`\bol{x = (46)/(16)}` =
`(23)/(8)`