3(y+3)+7(2y-8)-(y-1)=0

Question

asked Nov 16, 2021 15.9k views

2 Answers

Hadisur Rahman · Answer 1 · 2021-11-16T17:37:18+0000

Answer:

Explanation:

3(y+3)+7(2y-8)-(y-1)=0

3y + 9 + 14y - 56 - y + 1 = 0

16y - 46 = 0

16y - 46 + 46 = 0 + 46

16y = 46

16y/16 = 46/16

y = 23/8

Blai Pratdesaba · Answer 2 · 2021-11-21T10:22:19+0000

Answer:

We have this equation:

3(y+3)+7(2y-8)-(y-1)=0

First, we do the parenthesis:

$3y+9+14y-56-(y-1)=0\\$

When there is a minus (-) in front of a parenthesis, all signs change inside it:

$3y+9+14y-56-y+1)=0\\$

Now we operate:

16y-46=0

We add 46 on both sides:

16y - 46 + 46 = 0 +46

16y = 46

And divide 16 on both sides:

(16y)/(16)=(46)/(16)

$\bol{x = (46)/(16)}$ =
(23)/(8)