214k views
5 votes
Please help........................

Please help........................-example-1
User Gallaugher
by
4.5k points

1 Answer

2 votes

Answer:

a. (0,0), (2,0), (4,0)

b. (0,0)

Explanation:

To find the x-intercept points, you set the equation equal to 0.

0=x³-6x²+8x [factor out an x]

0=x(x²-6x+8) [factor (x²-6x+8)]

0=x(x-2)(x-4) [set each factor equal to 0]

x=0

x-2=0 [add both sides by 2]

x=2

x-4=0 [add both sides by 4]

x=4

Now, we know our x-intercept points: (0,0), (2,0), (4,0).

To find the y-intercept points, we know that it is located on the y-axis, meaning x=0. We plug in 0 for x, and we will know our y-intercept point.

y=(0)³-6(0)²+8(0) [multiply]

y=0

The y-intercept point is (0,0).

User JustRaman
by
5.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.