Question

Can you please help me with this

Answer 1

When we have exponents (being multiplied) in a parenthesis which also has an exponent, the exponent of the parenthesis gets multiplied by each one of the others. We have to distribute the outer exponent to each exponent inside, like:

`(a^n*b^m)^p = a^(n*p)*b^(m*p)`

If there are numbers but no exponents (inside), it also happens the same, but as the exponent of the parenthesis gets multiplied by 1, we can just put the exponent, like:

`(a*b)^p=a^p+b^p`

So, in our case we have what we have explained: two numbers, one of them with an exponent and the other without it in a parenthesis which also has an exponent, so we multiply that exponent by the ones of the numbers inside the parenthesis.

`(2^3*9)^(4)/(5)` =
`2^{3*(4)/(5)}*9^(4)/(5)` =
`2^(12)/(5)*9^(4)/(5)`

So the answer is
`2^(12)/(5)*9^(4)/(5)`

Answer 2

Answer: A

Explanation:

For this problem, we would distribute the outer exponent to each exponent inside. Once we distribute, we multiply the exponents together.

`2^(12)/(5) *9^(4)/(5)`