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Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in slope-intercept form.

1 Answer

4 votes

Answer:

y = -
(1)/(2) x +
(11)/(2)

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x - 6 ← is in slope- intercept form

with slope m = 2

Given a line with slope m then the slope of a line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(2) , thus

y = -
(1)/(2) x + c ← is the partial equation

To find c substitute (1, 5) into the partial equation

5 = -
(1)/(2) + c ⇒ c = 5 +
(1)/(2) =
(11)/(2)

y = -
(1)/(2) x +
(11)/(2) ← equation of perpendicular line

User Krishnan Sundaram
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