Answer:
0.69 g/cm^3
Step-by-step explanation:
Given that a small beaker has 50 mL of water in it. A small frog with a mass of 20 grams is dropped into the beaker. The water level rises to 79mL.
The volume of the frog will be:
79 - 50 = 29mL
Convert it to litre by dividing it by 1000
29/1000 = 0.029 L
Since 1L = 1000 cm^3
Convert it to cm^3 by multiplying it by 1000
0.029 × 1000 = 29 cm^3
Density = mass/volume
Substitute the mass and volume into the formula
Density = 20/29
Density = 0.6896 g/cm3
Therefore, the density of the frog is 0.69 g/cm^3 approximately