Question

There are three numbers. The first number is twice the second number. The third number is twice the first number. The sum of the three numbers is 112.

Answer 1

1st number = 36

Second = 16

Third = 64

Explanation:

We have 3 numbers

Let's call the second number g

Then the first would be , 2x g = 2g

Then the third would be twice the first = 2 x 2g = 4g

We add up all numbers and equate it to 112

2g + g +4g = 112

7g = 112

g = 112/7

g = 16

First number = 2g = 2x16 = 32

Second number = g = 16

Third number = 4g = 4x16 = 64

Therefore the numbers are 32, 16, 64.

I hope this helps!