Question

You want to estimate the mean amount of time college students spend on the Internet each month. How many college students must you survey to be 95% confident that your sample mean

Answer 1

752.95

Explanation:

Data provided in the question

The standard deviation of population = 210

The Margin of error = 15

The confidence level is 75%, so the z value is 1.96

Now the required sample size is

`= 1.96^2* (210^2)/(15^2)`

= 752.95

Hence, the number of college students spends on the internet each month is 752.95

Simply we considered the above values so that the n could come