G The velocity (V) of a particle is given by 5t2 meters, where t is in s. Find the acceleration of the particle at t=3s.

Question

asked Sep 2, 2021 74.8k views

1 Answer

Dmitry Spikhalsky · Answer 1 · 2021-09-06T20:33:32+0000

Answer:

Acceleration,
$a=45\ m/s^2$

Step-by-step explanation:

The velocity of a particle is given by :

V=5t^2

t is time in seconds

The acceleration in terms of velocity is given by :

$a=(dv)/(dt)\\\\a=(d(5t^2))/(dt)\\\\a=5* (t^3)/(3)$

We need to find the acceleration of the particle at t = 3 s. Put t = 3 s in the expression of a.

So,

$a=(5* 3^3)/(3)\\\\a=45\ m/s^2$

So, the acceleration of the particle at t = 3 s is
$45\ m/s^2$ .