Answer:
0.004394Joules
Step-by-step explanation:
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Energy stored in a capacitor = 1/2CV² where;
C is the capacitance of the capacitor
V is the potential difference across the plates
Given parameters
C = 13.0μF = 13 * 10⁻⁶F
V = 26.0V
Required
Energy stored in the capacitor
Substituting the values into the equation given;
E = 1/2 * 13 * 10⁻⁶ * 26²
E = 1/2 * 13 * 10⁻⁶ * 676
E = 1/2* 8788 * 10⁻⁶
E = 4394 * 10⁻⁶
Hence the Energy stored in the capacitor in Joules is 0.004394Joules