Question

A spinning top spinning at 16rad/s takes 88.9s to come to a complete stop. Find the angular acceleration of the top.

Answer 1

The angular acceleration of the top is 0.18 rad/s²

Step-by-step explanation:

Given;

angular velocity of the top, ω = 16 rad/s

time it takes to come to a complete stop, t = 88.9s

The angular acceleration of the top, is calculated as;

`\alpha = (\omega)/(t)`

α is the angular acceleration

ω is angular acceleration

t is the time

`\alpha = (\omega)/(t)\\\\\alpha = (16)/(88.9)\\\\\alpha =0.18 \ rad/s^2`

Therefore, the angular acceleration of the top is 0.18 rad/s²