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Given

mZAOC is a straight angle.
mZBOC = 6x + 29°
mZAOB = 3x + 124°
Find mZBOC:
O
с
A

Given mZAOC is a straight angle. mZBOC = 6x + 29° mZAOB = 3x + 124° Find mZBOC: O-example-1
User Arrtchiu
by
8.4k points

1 Answer

7 votes

Answer:

47°

Explanation:

Given that m<BOC = 6x + 29, m<AOB = 3x + 124, and m<AOC is a straight angle, therefore, m<AOC = 180°.

m<BOC +m<AOB = 180°

6x + 29 + 3x + 124 = 180

Solve for x

6x + 3x + 29 + 124 = 180

9x + 153 = 180

Subtract both sides by 153

9x = 180 - 153

9x = 27

Divide both sides by 9

x = 3

m<BOC = 6x + 29

Plug in the value of x

m<BOC = 6(3) + 29

m<BOC = 18 + 29 = 47°

User Christoph
by
8.7k points

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