Answer:
Given that
I = 1340 W/m²
µo = 4πx 10^-7 Tm/A
sc = 3 x 10^8 m/s
So to find the peak values of B we use
I = (c Bm²) / (2 µo)
1340 = (3 x 10^8 x Bm²) / (2 x 4πx 10^-7)
1340 = (3 x 10^8 x Bm²) / (25.12 x 10^-7)
(3 x 10^8 x Bm²) = 1340 x (25.12 x 10^-7)
(3 x 10^8 x Bm²) = 3.366 x 10^-3
Bm² = 3.366 x 10^-3 / 3 x 10^8
Bm² = 1.122 x 10^-11
Bm = 3.4 x 10^-6 T
Also to find the peak values of E we
use Em = c x Bm
Em = (3 x 10^8) (3.4 x 10^-6)
Em = 1.005 N/C