Question

An optical fiber made of glass with an index of refraction 1.50 that is coated with a material with index of refraction 1.30 has a critical angle of

Answer 1

A critical angle of 60.1°

Step-by-step explanation:

Let's say

n1 Refractive index of rarer medium

n2 Refractive index of denser medium

So using the relation

စc= Sin^ -1(n1/n2)

So

စc = Sin^-1(1.3/1.5) = 60.1°