Question

If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved through it?

Answer 1

Given :

Number of operations move through a pocket calculator during a full day's operation ,
`n=1.34 * 10^(20)` .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in one electron is :

`e^-=-1.6* 10^(-19)\ coulombs`

So , charge on n electron is :

`C=e^-* n\\C=-1.6* 10^(-19)* 1.34* 10^(20) \ C\\C=-21.44\ C`

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .