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If F is the midpoint of DE, DF =3x+5 and FE = 5x-19, Find DF

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Answer:

DF=41

Explanation:

It is given that F is the midpoint of DE. We know that, midpoint bisects the line segment. So,

DF=FE

3x+5=5x-19

Subtracting both sides by 3x

3x+5-3x=5x-19-3x

5=2x-19

Subtract both sides by 5

5-5=2x-19-5

0=2x-24

2x=24

x=12

So, the value of x is 12.

Put x = 12 in DF=3x+5

DF=3(12)+5

DF= 36+5

DF = 41

So, the value of DF is 41.

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