Question

show all work to multiply 3 plus the square root of negative 16 times 6 minus the square root of negative 64

Answer 1

3 + 16i

Explanation:

3 + √-16 * 6 - √-64

= √-16 * 6 = 24i; √-16 * 6; √-16 = 4i

= 4 * 6i multiply the numbers 4 * 6 = 24

= 24 i

√-64 = 8i; √64 apply a radical rule

= √-1 √64

= √64 i; √64 = 8

= 8i

= 3 + 24i - 8i

= 3 + 16i

Answer 2

`\Huge \boxed{3+16i}`

`\rule[225]{225}{2}`

Explanation:

`3+√(-16) * 6-√(-64)`

Using imaginary number rule :
`√(-n) =√(n) *i`

Where
`n` is a positive integer.

`3+√(16) *i* 6-√(64)*i`

`3+4i* 6-8i`

Multiplying.

`3+24i-8i`

Combining like terms.

`3+16i`

`\rule[225]{225}{2}`