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Find the perimeter and the area of the figure

perimeter: __ m

area: __ m²

Find the perimeter and the area of the figure perimeter: __ m area: __ m²-example-1
User Julien Sanchez
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2 Answers

15 votes
15 votes

Answer:

Area for small square: 25 because 5x5 equals 25

Area for rectangle: 77 because 11x7 equals 77

Area for the irregular shape: 102 because you must add 25 and 77 together

Explanation:

I'm sorry if I'm wrong. Have a nice day! <3 (I'm currently learning myself but I'm 100% sure I'm right)

User First
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2.6k points
7 votes
7 votes

Answer:

Your perimeter is 56m

Your area for your square is 25m²

Your area for your rectangle is 112m²

Your total area is 137m²

Explanation:

For area you need to multiply the length of two of the sides

5×5=25m²

For the rectangle you need the length of the bottom line and to do that you need to add 11m and 5m, which is 16

16×7=112m²

To get both areas together you need to add them

112+25=137m²

Now to get the perimeter you need to add all of the sides together. The blank side on the square is 5m because it is the same length as the side parallel to it. The blank side on the width of the rectangle is 7 because the line parallel to it is the same length. The blank on the bottom is themost difficult to find, but it isn't that hard. All you have to do is find the length of the lines parallel to it. So all you need to do is add 5 to 11, which is 16. If you wanted to you could also combine the left most lines lengths 7+5=12, but I am just going to do the number that we have.

5+5+5+11+7+16+7=56m so when you put all of that info together you get

P: 56m

A of sq: 25m²

A of rect: 112m²

TA: 137m²

User Damond
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2.8k points