Question

Part 2: NO LINKS!! NOT MULTIPLE CHOICE! Please help me​

Answer 1

(see attachment for tree diagram)

`\sf Probability\:of\:an\:event\:occurring = (Number\:of\:ways\:it\:can\:occur)/(Total\:number\:of\:possible\:outcomes)`

Part (a)

`\textsf{P(Head) and P(3)}=\sf (1)/(2) * (1)/(6)=(1)/(12)`

Part (b)

`\textsf{P(Tail) and P(even)}=\sf (1)/(2) * (3)/(6)=(3)/(12)=(1)/(4)`

Part (c)

`\textsf{P(not 6)}=\sf 1-\textsf{P(6)}=1-(1)/(6)=(5)/(6)`

`\implies \textsf{P(Head) and P(not 6)}=\sf (1)/(2) * (5)/(6)=(5)/(12)`

Part (d)

As the six-sided die does not have a side labelled "7", the probability of rolling a 7 is zero.

`\implies \textsf{P(Head) and P(7)}=\sf (1)/(2) * 0=0`