Answer:
![\boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}](https://img.qammunity.org/2021/formulas/mathematics/college/f2lir6swmaj0ol0yg4ma3u01kj5sutf1lm.png)
Option D is the correct option.
Explanation:
Given, x = 2 and y = 4
![\sf{(2x + 3y) / 4 - 2}](https://img.qammunity.org/2021/formulas/mathematics/college/iypurfxkpvxqhiy82lnkomts4892qmy5az.png)
plug the value of x and y
⇒
![\sf{ (2 * 2 + 3 * 4) / 4 - 2}](https://img.qammunity.org/2021/formulas/mathematics/college/36nblmgknu8u1pvdxsregrkr532q0t3kn7.png)
Multiply the numbers which are inside the bracket
⇒
![\sf{(4 + 12) / 4 - 2}](https://img.qammunity.org/2021/formulas/mathematics/college/ov7l3jitjy0b3tx1wtruil9yf7mj5q9dy0.png)
Add the numbers which are inside the bracket
⇒
![\sf{16 / 4 - 2}](https://img.qammunity.org/2021/formulas/mathematics/college/3qogte32qls8q6i5qmlfunh2gv1gqjlahd.png)
Divide 16 by 4
⇒
![\sf{4 - 2}](https://img.qammunity.org/2021/formulas/mathematics/college/yjf8slskftkgvb9t7gwz7rjyhr5yolf3hg.png)
Subtract 2 from 4
⇒
![\sf{2}](https://img.qammunity.org/2021/formulas/mathematics/college/pq8e3zlvnna6y8bcvmyyymfoe96lqhdgqg.png)
Hope I helped!
Best regards! :D