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If 12.3 grams of a substance burns in air to produce 15.9 grams of a compound, what mass of the air reacted?

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Answer:


m_(air)=3.6g

Step-by-step explanation:

Hello,

In this case, given the law of conservation of mass which states that mass cannot be created nor destroyed, since the produced mass of the compound is 15.9 g and the mass of the initial substance is 12.3 g we obtain the mass of air by applying the following equation:


m_(reactants)=m_(products)\\\\m_(substance)+m_(air)=m_(product)

Thus, solving for the mass of air we obtain:


m_(air)=m_(product)-m_(substance)\\\\m_(air)=15.9g-12.3g\\\\m_(air)=3.6g

Regards.

User Hidde
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