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A 1.75 gram perfect cube of wood has a side measure of 2.45 cm, what is the density of the wood?

User Emin Ayar
by
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1 Answer

3 votes

Answer:

0.119 g/cm³

Step-by-step explanation:

Step 1: Given data

Mass of the cube (m): 1.75 g

Side measure (l): 2.45 cm

Step 2: Calculate the volume of the cube

We will use the following expression.

V = l³

V = (2.45 cm)³

V = 14.7 cm³

Step 3: Calculate the density (ρ) of the cube

The density of the cube is equal to its mass divided by its volume.

ρ = m/V

ρ = 1.75 g/14.7 cm³

ρ = 0.119 g/cm³

User Nikhil Upadhyay
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