Question

0.200 grams of HCl is dissolved in 0.801 grams water. The density of the solution formed is 1.10 g/mL. What is the molarity of the solution

Answer 1

`M=6.03M`

Step-by-step explanation:

Hello,

In this case, since the molarity is computed by:

`M=(n_(solute))/(V_(solution))`

Whereas the solute is the hydrochloric acid, we compute the corresponding moles with its molar mass (36.45 g/mol):

`n_(solute)=0.200gHCl*(1molHCl)/(36.45gHCl) =0.00549molHCl`

Next, since the solution contains both HCl and water, we compute the volume in liters by using its density:

`V_(solution)=(0.200+0.801)g*(1mL)/(1.10g) *(1L)/(1000mL) =9.1x10^(-4)L`

Therefore, the molarity turns out:

`M=(0.00549mol)/(9.1x10^(-4)L)\\ \\M=6.03M`

Regards.