Question

Find the distance between (3,5)
and (7,-3). **(round to the nearest tenth.)

Answer 1

Explanation:

√(7-3)^2+(-8)^2

√16+64

√80

8.94

Answer 2

The answer is

8.9 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{( {x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(3,5)and (7,-3)

The distance between them is

`d = \sqrt{( {3 - 7})^(2) + ({5 + 3})^(2) } \\ = \sqrt{ ({ - 4})^(2) + {8}^(2) } \\ = √(16 + 64) \\ = √(80) \\ =4 √(5) \\ \: \: \: \: = 8.9442`

We have the final answer as

8.9 units to the nearest tenth

Hope this helps you