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Your physics teacher is giving you a special gift a box of mass 20 kg with a mystery surpise insie .the box is placed on a frictionsed table .what is the weigth of the box and normal reaction over it by the table ?

2 Answers

4 votes

Answer:


\Huge \boxed{\mathrm{196.2 \ N}}


\rule[225]{225}{2}

Step-by-step explanation:

Using weight formula:


\sf Weight = mass * acceleration \ of \ gravity


W=mg

The mass of the box is 20 kg.

The acceleration of gravity on Earth is 9.81 m/s².


W=(20)(9.81)


W=196.2

The weight of the box is 196.2 N.

The net force of the box is zero, since the box is at rest. The normal force is exerted upward on it by the table.


\rule[225]{225}{2}

User Tejasva Dhyani
by
6.8k points
0 votes

Answer:

F = 196.2 N

Step-by-step explanation:

Use Newtons law

F = m * a

F = 20 kg * 9.81 m/s²

F = 196.2 N

User GMA
by
6.2k points