Question

Find the number if 18 is taken away from 8 times of a number gives 30.

Answer 1

x =6

Explanation:

Translate into algebraic equation =

`8(x)-18= 30\\= 8x-13=30`

Let's solve for x

`\mathrm{Add\:}18\mathrm{\:to\:both\:sides}\\8x-18+18=30+18`

Simplify

`8x=48`

Divide both sides by 8

`(8x)/(8)=(48)/(8)`

Simplify

`x =6`

Answer 2

Let the number be x.

8 times that number would be 8x, and taking away 18 from it 8x - 18. Knowing the result of doing this is 30, we can write the following equation:

8x - 18 = 30

And solve it. First we pass the -18 to the sight umming:

8x = 30 + 18

8x = 48

Then the 8 which is multiplying to the right dividig:

x = 48/8 = 6

Now we verify we have done it preporly:

8x - 18 = 30

8 * 6 - 18 = 30

48 - 18 = 30 TRUE