Question

Vegetable oil has a specific heat of 1.67/* Calculate the heat required (in kilojoules) to raise the temperature of 500 g of

vegetable oil from room temp (20.0°C) to 150.0°C

Answer 1

`Q=108.55kJ`

Step-by-step explanation:

Hello,

In this case, we can compute the required heat by using the following equation:

`Q=mCp(T_2-T_1)`

Thus, by considering the given mass, specific heat and both initial and final temperature, we obtain:

`Q=500g*1.67(J)/(g\°C) *(150.0\°C-20.0\°C)*(1kJ)/(1000J) \\\\Q=108.55kJ`

Regards.