Question

The side lenghts of a square measures 10x+5. the side lenghts of a triangle are 30x,3x and 6x+30. the square and triangle have the same perimeter. find the perimeter

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Answer 1

58

Explanation:

We can use the Pythagorean theorem to find the area of the square for the third side.

The equation for the Pythagorean theorem is

a^2 + b^2 = c^2

where a and b are the lengths of the two legs of the triangle, and c is the length of the hypotenuse.

a^2 + b^2 = c^2

3^2+7^2=x^2

9+49=x^2

58=x^2
The area of the square for the third side of the triangle is 58 units^2 squared.

Answer 2

(10x+5)4 = 30x + 3x + 6x +30

40x + 20 = 39x + 30

X = 10

perimeter of the square= 420
perimeter of the triangle= 420