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A doppler radar sends a pulse at 6.00x10^9 hz. it reflects off some clouds, and returns to the radar 672 hz higher. what is the speed of the clouds?

User Mocybin
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1 Answer

6 votes

Answer:

v-rel = 16.8

Make sure to read the explaination so you can solve it yourself!

Step-by-step explanation:

I had this same question on Acellus, here is how I answered it:

Equation being used: Δf = 2*fο*vrel/c

( this equation can be found in the bottom of the lesson manual in the help tab)

Where,

Δf = change in frequency; 672

fο = frequency before being doppler shifted; 6.00 * 10^9

vrel = relative velocity; unknown

c = speed of light; 3.00 * 10^8

Now that we have written the numbers we know down, we must rearrange the equation for the velocity (vrel)

Starting Equation:

Δf = 2*fο*vrel/c

Multiply by c, then divide by 2fo to isolate vrel.

This will leave us with the equation:

Δfc/2fo, now we plug in the numbers

(672 * (3*10^8)) / (2* (6.00*10^9))

Once we plug this into the calculator, you should get

16.8

I hope this helped you, Wawawewa!

User Hdomos
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