Question

A football is kicked from ground level with an initial velocity of 23.8 m/s at angle of 42.5° above the horizontal. How long, in seconds, is the football in the air before it hits the ground? Ignore air resistance.

Answer 1

The value is
`t = 3.28 \  s`

Step-by-step explanation:

From the question we are told that

The initial velocity is
`u = 23.8 \  m/s`

The angle is
`\theta=  42.5^o`

Generally from the projectile motion equation we know that the time of flight is mathematically represented as

`t  =  (2 *  u  *sin (\theta ))/( g )`

=>
`t =  ( 2 *  23.8 *  sin (42.5))/(9.8 )`

=>
`t = 3.28 \  s`