Explanation:
Hey, there!
Here,
Given that:
![= 25 {x}^(2) - 4](https://img.qammunity.org/2021/formulas/mathematics/high-school/diklm3ayp5ffoxjm0clg6sj0qxyc29hxwp.png)
we need to find factor,
As it is in a^2-b^2 form as per its factor (a+b) (a-b), keeping same formula here,
25x^2 means (5x)^2
and 4 means 2^2
Now, it would be,
![= ( {5x)}^(2) - {2}^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/h65ebj4hhindxfnlkcptyn3xh4rhltvkpl.png)
![= (5x + 2)(5x - 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/kw3cixweb4zgwl2t8bfnwjqc6y1rf3qr2g.png)
Therefore, it's factor would be (5x+2)(5x-2).
Hope it helps....