Answer:
1st evening = 7 + 20 = 27 calls
2nd evening = 3 (20 ) = 60 call
3rd evening = 20 calls
Explanation:
total calls for the last three evenings = 107 phone calls
2nd evening = 3x as many calls as the 3rd evening
1st evening = 7 more calls than the 3rd evening.
find:
how many calls did she receive each evening?
let T (total) = 107
let x = 3rd evening.
let 2nd = 3x
let 1st = (7 + x)
T = 1st + 2nd + 3rd
107 = (7 + x) + 3x + x
107 - 7 = 5x
100 = 5x
x = 100 / 5
x = 20
therefore,
1st evening = 7 + 20 = 27 calls
2nd evening = 3 (20 ) = 60 call
3rd evening = 20 calls