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What is the number of terms in 4x+2x^2(3x-5)

1 Answer

3 votes

Answer:

12x^2-16x

Explanation:

4x+2x^2=4x(3x-5)

4x+4x(3x-5)

( 4x*3x-5)=12x^2-20x

4x+12x^2-20x

4x-20x= -16x

=12x^2-16x

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