Question

light of wavelength 587.5 nm illuminates a slit of width 0.75 mm. at what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.85 mm from the central maximum?

Answer 1

1.085m

Step-by-step explanation:

Using

a= lambda/sinစ

Sinစ= (587.5*10^-9) x 0.75*10^-3

= 0.000783

Sinစ=0.875*10^-3/d

0.000783= 0.875/d

d= 1.085m