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2 votes
A cylinder has a volume of 320 cubic inches and a height of 5 inches.

What is the radius of the cylinder?
O A. 4 inches
B. 8 inches
C. 16 inches
D. 32 inches

User Mrdeadsven
by
6.2k points

2 Answers

5 votes

Answer:


\Huge \boxed{\mathrm{4.51 \ inches}}


\rule[225]{225}{3}

Explanation:


V=\pi r^2 h

The volume is 320 in³.

The height is 5 in.


320=\pi r^2 * (5)

Solving for
r.

Dividing both sides by 5.


64=\pi r^2

Dividing both sides by
\pi.


20.371833=r^2

Taking the square root of both sides.


r= 4.513517

The radius is 4.51 inches.


\rule[225]{225}{3}

User Mkell
by
7.8k points
6 votes

Answer:

The radius is 8 inches

Explanation:

The volume of a cylinder is given by

V = pi r^2 h

Assuming you mean 320 pi for the volume

320 pi = pi r^2 ( 5)

320 =5pi r^2

Divide each side by 5pi

320 pi / 5pi = 5 pi r^2 / 5pi

64 = r^2

Take the square root of each side

sqrt(64) = sqrt(r^2)

8 = r

The radius is 8 inches

User Alberto Cerqueira
by
6.7k points