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If m∠ TUW = (5x + 3)°, m∠WUV=(10x-5)°, and m∠TUV=(17X-16)°, find each measure

User Kathara
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1 Answer

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Answer: m∠ TUW = 38°

m∠WUV = 12°

m∠TUV = 103°

Explanation:

Given: m∠ TUW = (5x + 3)°, m∠WUV=(10x-5)°, and m∠TUV=(17x-16)°

Since, m∠TUV = m∠ TUW + m∠WUV

So, 17X-16 = (5x + 3) + (10x-5)

⇒ 17X-16 = 5x + 3 + 10x-5 [open parenthesis]

⇒ 17X-16 =5x + 10x +3 -5 [combine like trems]

⇒ 17X-16 =15x -2

⇒ 17X -15x = -2+16 [subtract 15x and add 16 on both sides]

⇒ 2x = 14

⇒ x= 7 [divide both sides by 2]

Now, m∠ TUW = (5(7) + 3)°= 38°

m∠WUV=(10(7)-5)° = 12°

m∠TUV=(17(7)-16)° = 103°

Hence, m∠ TUW = 38°

m∠WUV = 12°

m∠TUV = 103°

User Sayed
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