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There are 12 yellow, 5 blue, 14 red, and 9 green marbles in a bag. a marble is chosen at random, not replaced, then another marble is chosen.

User Sudharshan
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2 Answers

7 votes

Final answer:

The probability of drawing a yellow marble and then a green marble from a bag without replacement is 27/200 or approximately 0.135.

Step-by-step explanation:

The probability of drawing a yellow marble and then a green marble from a bag without replacement can be calculated as follows:

First, we calculate the probability of drawing a yellow marble on the first draw. There are 12 yellow marbles out of a total of 12+5+14+9 = 40 marbles in the bag.

So, the probability is 12/40.

Next, we calculate the probability of drawing a green marble on the second draw. After drawing a yellow marble, there are 11 yellow marbles and 9 green marbles left in the bag.

So, the probability is 9/20.

To find the probability of both events happening together, we multiply the probabilities: (12/40) × (9/20) = 27/200 or approximately 0.135.

User Monacraft
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8.8k points
8 votes
The color of the marble would problem be red
User Soroush Mirzaei
by
7.6k points

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