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Liquid methanol (CH3OH) reacts with oxygen gas to form carbon dioxide gas and water vapor. Express your answer as a chemical equation. Identify all of the phases in your answer.

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Answer:


2CH_3OH_((l)) + 3O_2_((g)) --> 2CO_2_((g)) + 4H_2O_((g))

Step-by-step explanation:

The reaction between methanol and oxygen can be expressed as an equation below:


CH_3OH + O_2 --> CO_2 + H_2O_

However, the equation is not balanced as the number of the molecule of each atom on the right-hand side and the left-hand side is not the same. The balanced equation showing the phases of all the reactants and products is as below:


2CH_3OH_((l)) + 3O_2_((g)) --> 2CO_2_((g)) + 4H_2O_((g))

Two molecules of liquid methanol react with three molecules of oxygen gas to give 2 molecules of carbon dioxide gas and four molecules of water vapor.

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