Question

Two identical guitar strings are prepared such that they have the same length ( 0.62 m ) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the second harmonic. The other string is plucked in a different location, primarily exciting the third harmonic. The resulting sounds give rise to a beat frequency of 324 Hz . What is the wave propagation speed on the guitar strings?

Answer 1

The speed is 401.76m/s

Step-by-step explanation:

To find the fundamental frequency we use

3rd.harmonic - 2nd.harmonic = 324Hz

And we know that

f=v/2L

So v=f2L

v= 324 x 2 x 0.62= 401.76m/s