Answer:
1.1 x 10^10J
Step-by-step explanation:
∫x2,x1F(x)dx = ∫7.5 x 10^4 m ,0 (αx3+β)dx.
(αx4/4+βx) 7.5 x 10^4 m, 0
((6.1×10−9N/m3)( 7.5×104m)^4)/4 - (4.1×106N)( 7.5×104m) -0)
= 4.825 x 10^10 - 30.75 x 10^10
= 25.925 x 10^10J
= 2.5925 x 10^11J
The kinetic energy KE2 is,
KE2 = KE1 + ∫x2,x1F(x)dx
= 2.7×1011J - .5925 x 10^11J
= 0.1065 x 10^11J
= 1.1 x 10^10J